Color Analysis Lab Report

Brilliant Essays
Introduction
In color reproduction, gamut or the color gamut is a certain complete subset of colors, which can be accurately represented in a given circumstance such as given color space [1]. In another words gamut literally means the total range of possibilities that can be accomplished from red, green and blue (RGB) for a particular device [2]. If certain color cannot be reproduced accurately there is a way how to calculate the color difference by adequately describing the color by numerical values. Delta E (∆E) is the mathematical difference between two samples and is computed as distance in CIELAB space between two colors.
The CIELAB color space is used as the basis of most color difference systems because the axes of CIELAB are orthogonal, color difference can be defined as the distance in three dimensional space between the coordinates for two colors [3].
…show more content…
Color processing model for matrix based conversion [3].

Display profiles are always matrix-based and they require small number of measurements to determine phosphor chromaticities and display intensity. Monitor profiles can be created in profile-creation application. It is also possible to create display profile without measurements using utilities such as Adobe Photoshop but these are likely to be less accurate than a profile based on measurements [3]. Methods
To form a color with RGB we use three light beams (one red, one green, and one blue). Each of the three beams is called a component of that color, and each of them can have an arbitrary intensity, from fully off to fully on, in the mixture [4].
To generate the needed data for computing color difference, gamut visualization and creating the ICC profile test chart containing series of colors was displayed on both devices sequentially, for each beam (R, G and B) an arbitrary intensity of 64, 128, 192 and the primary 255 was displayed. In addition to these colors yellow, magenta, cyan, black and white were displayed

Related Documents

  • Improved Essays

    The three colours are spread evenly on the circle over 360. Red is assigned to an angle of 0, while green to an angle of 120, blue to an angle of 240 and remaining colours can be found on the other points. Grey scale is located in the centre of the hue circle because all shades of grey are an even combination of the three main colours. The saturation of a colour is the purity of a colour and tells the amount of white contained in the pure spectral colour. To represent the two hue and saturation, a vector pointing to the pure spectral colour is used and the value of this vector gives the saturation.…

    • 1019 Words
    • 5 Pages
    Improved Essays
  • Decent Essays

    End-Of-Chapter Quiz

    • 680 Words
    • 3 Pages

    (1 point) Correct answer DSUM 13) The use of two or more conditions on the same row—all of which must be met for the records to be included in the results. (1 point) Correct answer Compound criteria 14) A database function that determines the number of occurrences of a specified condition in a database. (1 point) Correct answer DCOUNT 15) Formatting characteristics that are applied to cells when the value in the cell meets a specified condition are called: (1 point) Correct answer Conditional formats 16) In Excel, you can insert an image of an open window called a: (1…

    • 680 Words
    • 3 Pages
    Decent Essays
  • Improved Essays

    The most intense color for making light orange is yellow. Our ratio of yellow to red to make light orange is 4:1. If we wanted a darker color of orange we would have more red filters but our color was light so to get the right color we continued to add yellow filters until we got light orange. Also, because blue is the commentary color for yellow we can look at the adding of yellow filters as taking out more of the blue color because we are doing subtractive mixing. With four yellow filters we are taking out four times as much blue.…

    • 799 Words
    • 4 Pages
    Improved Essays
  • Improved Essays

    Dichromatic color perception is involved with the ability to see some color but is caused by a deficit in one of the three cone receptors, that is only two work. Protanopes are dichromats that have a deficit in the "red" cone, deutranopes have a deficit in the "green" cone and tritaneropes have a deficit in "blue" cones. Images of the color these people would be able to see is in figure 1 on page 6. Anomalous trichromatic color vision happens when wavelengths get mixed in different proportions than a regular trichromatic. This leads to one being less efficient at discriminating between wavelengths of color closer together.…

    • 1570 Words
    • 6 Pages
    Improved Essays
  • Superior Essays

    examples of white-tuning Potential issues • The wiring could be complex because the controllers of intensity and CCT are separate. • Low efficiency compared to non-tunable white LEDs. Full-color tuning Also referred to as RGB, RGBA, RGBW, spectrally tunable and “color changing”, full-color tunable products often consist of 3 or more LED sets. The individual LEDs can be narrow-band LEDs (producing a “pure” color, usually RGB), or coated LEDs. The monochromatic LEDs are usually red, green and blue (the primary colors of light, RGB), and can be augmented with amber (A) and white (W).…

    • 901 Words
    • 4 Pages
    Superior Essays
  • Great Essays

    Secondly, a dischormat needs two wavelengths in order to match all the other wavelengths within the spectrum. An example of this is shown in example 2 (c). An anomalous trichromat needs only three wavelengths in order to match any wavelengths, similar to how a normal trichromat does. But, the anomalous trichromat is not as distinct as a trichromat at determining within the wavelengths which are close together. (Put Citation…

    • 1564 Words
    • 7 Pages
    Great Essays
  • Superior Essays

    Facial Recognition Essay

    • 1426 Words
    • 6 Pages

    P_I= I ̂/I^* where I ̂ equals correctly identified and I* represents the size of the probe set. The final comparisons are made by using all pairs for (PI,PJ) and for all of the ROC values which were measured by letting the ROC = R_k/P. As with the algorithms already discussed, the Linear Discriminant Analysis (LDA) model begins with Gaussian data. LDA makes use of two values, the mean and the variance, which are produced for each class. Classes can be thought of as facial features such as chins, noses, eyes, ears, hair lines, hair styles, etc.…

    • 1426 Words
    • 6 Pages
    Superior Essays
  • Improved Essays

    SHAH How to do HDR photography (lions) HDR Photography HDR (High Dynamic Range) photography is a form of image processing that uses a series of images captured at different exposures to produce one, amazing photo. The dynamic range is a term used to infer to the ratio of darkness to the light. The idea is usually to compress the compress the light and have it appear on the final processed photo or computer in the same manner the eyes sees it. According to Photography.TutPlus, a good digital camera can capture a dynamic range in the ratio of 1,000:1, unlike the human eye, which can see a scene with 10,000:1. This means the human eye is much more capable of capturing wide variety of brightness compared to the camera.…

    • 883 Words
    • 4 Pages
    Improved Essays
  • Great Essays

    Figure 4 shows a normalization image of iris template size [20 x 240] is taken from CASIA database and split it into four block size [10 x 120]. Then the first blocks are taken and apply PSO to find the best edge of the crypt. Figure 5 shows a transformation of the split block using a different type of method. Some of the objects ' intensity is very similar to the background of the image and some shapes are more unequal. In figure 4, iris template image of size [20 x 240] have been split into 4 blocks of size [10 x 120] using mat2cell, indexing, block proc and matrix technique.…

    • 1827 Words
    • 8 Pages
    Great Essays
  • Great Essays

    Object Tracking Essay

    • 1558 Words
    • 7 Pages

    Morphological shape of the object can be extracted by the intersection of the positive and negative distribution of the sub-windows, as shown in Figure 8. Fig. 8. Morphologic characteristics map of the detected object. Green area shows the largest frequency of the object histogram, and red area is extraneous to the object color Next step of the tracking is to provide a label to the feature points, which belongs within the positive sub-window.…

    • 1558 Words
    • 7 Pages
    Great Essays