The statistical test used in this experiment was a Chi-square test because it measures the goodness of fit. There were 370 trials performed in the overall experiment. The sample size in the experiment was 740. Each cricket whether it was labeled intruder or resident had an observed and expectant number times it should win. For the resident crickets, it was expected that the cricket would win 185 times in the experiment. The observed value was calculated to be 238 wins in the experiment as well. The intruder cricket was also expected to win 185 times in the experiment but the actual value was calculated to be 132. The Chi-square value was 30.368 and there was 1 degree of freedom. The p-value was less than 0.0001. From all the data that was collected, notice that the null hypothesis was rejected as the value was less than 0.05.
In order for further investigation in the experiment, the house cricket experiment helped what was being understood house cricket behavior with respect to residency. The null hypothesis revealed that the number of observed wins of the resident cricket will be equal to 50 percent is incorrect which makes the alternative hypothesis was proven correct during the Chi-squared testing. …show more content…
First of all, the experiment was performed in a classroom that had minimal resources to conduct the experiment. The class was limited to study the cricket’s aggression for a couple in the classroom of hours instead of several weeks as is usually done in a lab. Second, the same group of crickets were used for every lab that was held during the week. Since the same crickets were used, by the end of the week, the crickets had been tested on so many times and this could have affected the results in other lab classes. An example would be that Monday’s lab might have had the resident cricket winning 50 percent or more of interactions than a lab that was held later in the
In order for further investigation in the experiment, the house cricket experiment helped what was being understood house cricket behavior with respect to residency. The null hypothesis revealed that the number of observed wins of the resident cricket will be equal to 50 percent is incorrect which makes the alternative hypothesis was proven correct during the Chi-squared testing. …show more content…
First of all, the experiment was performed in a classroom that had minimal resources to conduct the experiment. The class was limited to study the cricket’s aggression for a couple in the classroom of hours instead of several weeks as is usually done in a lab. Second, the same group of crickets were used for every lab that was held during the week. Since the same crickets were used, by the end of the week, the crickets had been tested on so many times and this could have affected the results in other lab classes. An example would be that Monday’s lab might have had the resident cricket winning 50 percent or more of interactions than a lab that was held later in the