The purpose of this lab was to find the optimal temperature for the highest efficiency of Catalase. Catalase is a common enzyme almost present in all living organisms and was obtained by extracting the juice out of potatoes in a complex process that could be a lab itself. It was hypothesized that as the temperature was increased the rate at which the Catalase reactions would be speeded up. A 1% solution of Hydrogen Peroxide was placed in the Catalase and the speed at which the reaction occurred was measured with a stopwatch in seconds. (The stopwatch was stopped once a small filter paper disk soaked in the Hydrogen Peroxide rose) The reactions took place under four different conditions. Each condition gave different results for the speed
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The temperatures tested were 0 degrees Celsius, 21 degrees Celsius, 38 degrees Celsius, and 103 degrees Celsius. The mean and standard deviations for each go as followed: the Catalase in the 0 degrees Celsius test had a mean and standard deviation of 46 sec +- 4.47 seconds, the Catalase in the 21 degrees Celsius test had a mean and standard deviation of 54 sec +- 17.58 seconds, the Catalase in the 38 degrees Celsius test had a mean and standard deviation of 44 sec +- 6.48 seconds, and the Catalase in the 103 degree Celsius test had a mean and standard deviation of 240 +- 0 because the reaction never happened for this test. The hypothesis was rejected because the boiling temperature actually denatured the enzyme and prevented it from causing a reaction. The body temperature test proved to have the best effects on reaction time it had the lowest mean at 44 seconds. The results showed that the enzyme, Catalase, worked most efficiently at body temperature and this could be because Catalase is present in living organisms and works best in that …show more content…
The hydrogen peroxide and Catalase are to react with each other later in the experiment. That reaction will be 2 H2O2 (liquid) -----> 2 H2O (liquid) + O2 (gas). Little circle disks were punched out of filter paper. The disks will be submerged in catalase and then placed into the hydrogen peroxide. A beaker about half full of hydrogen peroxide was prepared for the later reaction. We used four test tubes to make solutions of 2.5 mL of distilled water and 2.5 mL of Catalase. Since our goal was to measure catalase reaction time under varying temperatures, we prepared four different temperatures for the Catalase to be submerged in before it was mixed with the hydrogen peroxide. The different temperatures included a cold sample (0 degrees Celsius), a room temperature sample (21 degrees Celsius), a body temperature sample(37 degrees Celsius), and a boiling sample (103 degrees Celsius). We made sure to measure the exact degrees in Celsius. We placed a test tube of the 2.5 mL of catalase and hydrogen peroxide into each temperature for five minutes. After the five minutes was up, we submerged the little filter paper disks into each Catalase with the use of tweezers for five seconds each. We placed each disk directly onto the bottom of the beaker with the hydrogen peroxide in it and then started a stopwatch to time how long it took for the
The temperatures tested were 0 degrees Celsius, 21 degrees Celsius, 38 degrees Celsius, and 103 degrees Celsius. The mean and standard deviations for each go as followed: the Catalase in the 0 degrees Celsius test had a mean and standard deviation of 46 sec +- 4.47 seconds, the Catalase in the 21 degrees Celsius test had a mean and standard deviation of 54 sec +- 17.58 seconds, the Catalase in the 38 degrees Celsius test had a mean and standard deviation of 44 sec +- 6.48 seconds, and the Catalase in the 103 degree Celsius test had a mean and standard deviation of 240 +- 0 because the reaction never happened for this test. The hypothesis was rejected because the boiling temperature actually denatured the enzyme and prevented it from causing a reaction. The body temperature test proved to have the best effects on reaction time it had the lowest mean at 44 seconds. The results showed that the enzyme, Catalase, worked most efficiently at body temperature and this could be because Catalase is present in living organisms and works best in that …show more content…
The hydrogen peroxide and Catalase are to react with each other later in the experiment. That reaction will be 2 H2O2 (liquid) -----> 2 H2O (liquid) + O2 (gas). Little circle disks were punched out of filter paper. The disks will be submerged in catalase and then placed into the hydrogen peroxide. A beaker about half full of hydrogen peroxide was prepared for the later reaction. We used four test tubes to make solutions of 2.5 mL of distilled water and 2.5 mL of Catalase. Since our goal was to measure catalase reaction time under varying temperatures, we prepared four different temperatures for the Catalase to be submerged in before it was mixed with the hydrogen peroxide. The different temperatures included a cold sample (0 degrees Celsius), a room temperature sample (21 degrees Celsius), a body temperature sample(37 degrees Celsius), and a boiling sample (103 degrees Celsius). We made sure to measure the exact degrees in Celsius. We placed a test tube of the 2.5 mL of catalase and hydrogen peroxide into each temperature for five minutes. After the five minutes was up, we submerged the little filter paper disks into each Catalase with the use of tweezers for five seconds each. We placed each disk directly onto the bottom of the beaker with the hydrogen peroxide in it and then started a stopwatch to time how long it took for the