Determining the Percentage Yield of a Chemical Reaction
Question:
What is the percentage yield of the reaction of sodium carbonate and calcium chloride dihydrate (the dihydrate must be included with the molar mass calculation)? Predictions:
Predict the mass of sodium carbonate and calcium chloride dihydrate that will be required to produce 1.90 grams of calcium carbonate:
Therefore, the predicted mass of sodium carbonate is 2.0 grams and the predicted mass of calcium chloride dihydrate is 2.8 grams.
Materials:
2 Beakers (150 mL) Calcium chloride Sodium carbonate Stirring rod Electronic balance Goggles Graduated cylinder (10 mL) Distilled water Funnel Filter paper (12.5 cm) Scoopala Erlenmeyer flask (250 mL)
Safety …show more content…
Mass of dry filter paper 0.70 grams
Mass of Calcium carbonate and filter paper 2.58 grams
Mass of calcium carbonate 1.88 grams
One source of error that occurred during our experiment was spilling the mixture. While we were filtering the mixture, we spilled a small drop of the mixture onto the counter. Another error that could've occurred during this experiment was with the measuring device used because whenever we measured an object, if we moved the object to the middle or side of the electronic balance, it would show a number differing by approximately 0.1 gram each time. This error occurred due to our lack of attention, after pouring the mixture into the erlenmeyer flask. In order to attain an improved percentage yield, we will hold the beaker with the mixture steady on top of the flask before putting it back on the counter. Since we were running out of time, we rushed and caused a small remainder of the mixture to drop down the beaker. Percent Yield=(Experimental Yield)/(Theoretical Yield) x100% = 1.88/1.90 x 100% = 98.9% ~
Question:
What is the percentage yield of the reaction of sodium carbonate and calcium chloride dihydrate (the dihydrate must be included with the molar mass calculation)? Predictions:
Predict the mass of sodium carbonate and calcium chloride dihydrate that will be required to produce 1.90 grams of calcium carbonate:
Therefore, the predicted mass of sodium carbonate is 2.0 grams and the predicted mass of calcium chloride dihydrate is 2.8 grams.
Materials:
2 Beakers (150 mL) Calcium chloride Sodium carbonate Stirring rod Electronic balance Goggles Graduated cylinder (10 mL) Distilled water Funnel Filter paper (12.5 cm) Scoopala Erlenmeyer flask (250 mL)
Safety …show more content…
Mass of dry filter paper 0.70 grams
Mass of Calcium carbonate and filter paper 2.58 grams
Mass of calcium carbonate 1.88 grams
One source of error that occurred during our experiment was spilling the mixture. While we were filtering the mixture, we spilled a small drop of the mixture onto the counter. Another error that could've occurred during this experiment was with the measuring device used because whenever we measured an object, if we moved the object to the middle or side of the electronic balance, it would show a number differing by approximately 0.1 gram each time. This error occurred due to our lack of attention, after pouring the mixture into the erlenmeyer flask. In order to attain an improved percentage yield, we will hold the beaker with the mixture steady on top of the flask before putting it back on the counter. Since we were running out of time, we rushed and caused a small remainder of the mixture to drop down the beaker. Percent Yield=(Experimental Yield)/(Theoretical Yield) x100% = 1.88/1.90 x 100% = 98.9% ~