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10 Cards in this Set
- Front
- Back
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Principal = P Amount = A Time = T Rate = R Simple Interest = S.I |
A = P + S.I S.I = R * T |
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P=400₹, rate=8%, time=4years ,amount=? |
1yr=8% 4yr=32% S.i= 400x(32/100) = 128 |
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P=8000 S.i=1280 T=4yrs Rate=? |
4yrs=1280 1yrs=320 (320/8000)×100= 4% |
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Amount=650₹,R=10%,T=3yr,P=? |
P=100% 1yr=10% 3yr=30% A=(100+30)% 130%=650₹ 100%=500₹ P= 500 |
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An amount of 45000₹ becomes 77400₹ on simple interest in eight years. What is the rate of interest per annum ? |
P=45000 A=77400 S.i 8yrs=32400 S.i 1yrs=4050 (4050/45000)×100= 9% |
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The sum of money that will give 1₹ as interest per day at the rate of 5% per annum simple interest is ? |
Interest of a day = 1₹ Interest of one year = 365₹ 5%=365₹ 10%=730₹ 100%(P)= 7300₹
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At some rate of si, a lent 6000₹ to 'b' and 1500 to 'c' for 4 years and received ₹ 2100 as interest from both of them together. The rate of si pa was? |
4 yrs= 2100₹ 1yrs= 525₹ 6000+1500=7500₹ Rate=(525/7500)×100= 7% |
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'A' lends ₹2500 to 'B' and certain money to 'C' at the same time for 7% annual si. If after 4 years he receives 1120₹ as total as si. The sum lent to 'c' was? |
4yrs= 1120 1yrs= 280 7%=280 1%=40₹ 100%=4000₹ B=2500₹ C= 1500₹ |
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The SI on 36000₹ for the period from 5th jan to 31st may 2013 at 9.5% pa is |
6th jan - 31st jan= 26days Feb=28days(non leap) March=31days April=30days May=31days Total=146 days 365days= 1yr 146days= 2/5yrs 36000×(9.5/100)×(2/5)= (36000/100)×(19/2)×(2/5) = 1368₹ |
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500₹ was invested at 12% pa si and a certain sum of money invested at 10% p.a SI. If si on both after 4 years is 480₹. The latter sum of money is |
1st 1yr = 12% 4yr= 48% 500×(48/100)=240₹ 2nd 480-240=240₹ 4yr=240₹ 1yr=60₹ 10%=60₹ 100%(p)= 600₹ |
