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33 Cards in this Set

  • Front
  • Back
Limit in R3
For a function to be continuous at a particular point it must approach a specific value from all directions.
Partial Derivative notation
If written f sub "variables" then you do the differentiation in the order the variable appear from left to right.

If it is written ∂/∂x∂y you start at the bottom right and move backwards towards the left.
Clairaut's Theorem
If Fxy and Fyx are both continuous then Fxy(x,y)=Fyx(a,b)
Equation of the tangent plane to the surface z=f(x,y) @ point (x0,y0,z0)
z - z0= Fx(x0,y0) (x-x0) +Fy(x0.y0) (y-y0)
Mean Value Theorem
F(x,y)-F(a,b)=∂f/∂x(a,b) * (x-a) +∂f/∂y (a,b) * (y-b) +e1(x-a) +e2(y-b)

Note: e1 and e2 are error factors and go to zero as x,y go to zero.
Differential
If z=f(x,y)
∂z= Fx(x,y) + Fy(x,y) = ∂f/∂x dx +∂f/∂y dy
The Chain rule
if q=f(a,b,x,y), x=f(t), y=g(t), a=(s,t), b=p(s)

∂q/∂t= (∂f/∂x)(dx/dt) +(∂f/∂y) (dy/dt) + (∂f/∂a) (da/dt)

∂q/∂s= (∂f/∂a)(da/ds) + (∂f/∂b)(db/ds)
Variable Types for Chain rule
Let z=f(x,y), x=g(s,t), y=h(q,r)

z is the dependent variable
x,y are called intermediate variables
q,r,s,t are independent variables.
Directional Derivative
∇f ∙ u (Where u is a unit vector in any direction)

The result is always a scalar.
Maximum or Minimum rate of change in 3 variables
It is |∇f(x,y,z)|

A Max is when u is in the same direction as the gradient

A min is when it is in the opposite direction as the gradient vector.
Finding minima and maxima
Take first order partial derivatives with respect to all variables and set them all equal to zero.

After that make a list of critical points and use that along with the extreme points of the Domain and Range to text in the original equation and see what the max and min values are.
The "D" test
D= Fxx(a,b)Fyy(a,b) -[Fxy(a,b)]^2

a.) D > o and Fxx(a,b) >0 it is a min
b.) D > 0 and Fxx < 0 it is a max
c.) D< 0 Saddle point
d.) D=0, inconclusive.
Fubini's Theorem
If our function is continuous along the entire rectangular domain the order of integration doesn't matter.
Type I Region
A region is considered type I if we integrate "y" first and y is described as a function of x.

This means the first way we integrate will cause us to draw vertical lines if we are going from lower to upper bounds.
Type II Region
This means that we integrate with respect to x first. We will have x expressed as functions of y and when we first draw our lines to find the shape it will be horizontal lines.
Polar Basics
x=r cos(Θ)
y= r sin(Θ)
r^2=x^2 +y^2

DO NOT FORGET THE EXTRA R WHEN CHANGING TO POLAR
∫sec^2(x)
tan (x)
∫csc^2(x)
-cot(x)
∫sec(x)tan(x)
sec(x)
∫tan(x)
ln |sec(x)|
∫sin^2(x)
1/2x -1/4 sin(2x)
∫cos^2(x)
1/2x +1/4sin(2x)
∫tan^2(x)
tan(x) -1
∫x sin(x)
sin(x) - x cos(x)
∫x cos(x)
cos(x) +x sin(x)
sin^2(x) +cos^2(x)
1
cos(2x)
cos^2 (x) -sin^2(x)
sin(2x)
2sin(x)cox(x)
sin(x)
±√(1-cos^2(x))
∂ sec(x)
sec(x)tan(x)
∂ tan(x)
sec^2(x)
∂ csc(x)
-csc(x)cot(x)
∂ cot(x)
-csc^2(x)