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39 Cards in this Set

  • Front
  • Back

solving for intercepts

for x, make y=0; for y, make x=0

circle equation

(x-h)^2+(y-k)^2=r^2

getting radius from point on circle

plug the point coordinates (x,y) into the circle equation with (h,k); solve for r

slope-intercept form

y=mx+b

ratio vs. rate

if x and y axis have same unit of measure, ratio; if x and y axis have different unit of measure, rate

point-slope form

y-y1=m(x-x1)

standard (general) form

ax+by+c=0

perpendicular line slope

negative reciprocal of initial slope (-1/m)

Vertical line test

if a vertical line intersects the graph more than once, it's not a function

domain

set of all values for which the function is defined (independent variable x)

standard notation (for domain)

something like x>1 or 0

Interval notation (for domain)

e.g. [-2, 6) ([] for inclusive, () for exclusive)

range

set of all values taken on by the dependent variable (y value)

piecewise-defined function

the f(x){ function; different functions depending on x-value

one-to-one function

to each value of the dependent variable, there corresponds exactly one value of the independent variable

horizontal line test

used to check if a function is one-to-one; same as vertical line test but horizontal

(f○g)(x)

is f(g(x))

composite of f with g

different wording for (f○g)(x)

finding inverse functions

replace f(x) with y, then swap x and y and solve for x; e.g. f(x)=x+1 would turn into x=y+1 which would turn into y=x-1 which would then be f

If f has an inverse, f must be ________

one-to-one

Dividing-out technique

dividing the numerator by the denominator to get an equation where the limit exists

rationalizing the numerator

multiplying the function by the conjugate of the numerator (e.g. (√(x+1)+1)/x * (√(x+1)-1)/(√(x+1)-1) )

one sided limits

when the limit doesn't exist at a point and differs from the left side (-) and the right side (+)

Continuous functions

functions that are not broken at a point; have no holes, jumps, or gaps

getting the continuity of a function with a hole

even if the point is filled, given a gap at x, with the graph going from -∞ to ∞, (-∞, 0), (0,∞)

polynomials and continuity

polynomials are always continuous in the intervals they are defined

step function

looks like stairs; functions consist of lines that shift up a certain amount when x changes to another integer; not continuous

vertical asymptote

f(x) approaches infinity at a point x; usually occurs in a function such as f(x)=1/x when x=0 and division by 0 occurs

removable discontinuities

discontinuities you can divide out; no vertical asymptote at the location, only a hole

horizontal asymptote

when y does not reach a certain value; occurs when finding a limit at ±∞

degree

power of the highest term (e.g. x^2+2x+1 would have a degree of 2

leading coefficient

the coefficient of the highest term (e.g. 3x^3+2x+1 would have a leading coefficient of 3)

finding horizontal asymptotes

given a function f(x)=p(x)/q(x), if the degree of q(x) is higher than that of p(x), it is at 0; if the degree of p(x) is equal to that of q(x), it is at a/b, a being the leading coefficient of P and b being the leading coefficient of q; if the degree of p(x) is higher than that of q(x), no horizontal asymptote

horizontal asymptote at 0

degree of q(x) given f(x)=p(x)/q(x) is higher than that of p(x)

horizontal asymptote at a/b

degree of p(x) and q(x) are the same given f(x)=p(x)/q(x); a and b are leading coefficients of p(x) and q(x), respectively

no horizontal asymptote

degree of p(x) is greater than that of q(x) given f(x)=p(x)/q(x)

horizontal asymptote of f(x)=3x/2x^2

0

horizontal asymptote of f(x)=4x^2/8x^2

4/8=1/2

horizontal asymptote of f(x)=3x^2/x

N/A