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37 Cards in this Set

  • Front
  • Back
Effective nuclear charge trend
Increases L --> R
Not much change T --> B
Covalent radius trend
Decreases L --> R
Increases T --> B
Ionisation energy trend
Increases L --> R
Decreases T --> B
Electronegativity trend
Increases L --> R
Decreases T --> B
Inert pair effect
P-block elements often form compounds in which they are in an oxidation state 2 less than the group oxidation state. Increasing tendency for the s2 pair not to be used in bonding as you go down the group. Bond energies also fall - not enough to compensate for promoting an s electron to make it available for bonding.
How does difference in electronegativity affect a bond strength?
A greater difference in electronegativity between two elements will lead to a stronger bond between them
How do multiple bonds change going down a group?
Multiple bonds decrease in strength going down a group due to weakening pi bonds and poorer overlap
Effect of size on coordination number
Larger atoms can support higher coordination numbers
Trends between groups 14-17
One extra electron per atom going from 14 - 15, 15 - 16 etc.
Group 14 - 4 bonds
Group 15 - 3 bonds, 1 l.p.
Group 16 - 2 bonds, 2 l.p's
Group 17 - 1 bond, 3 l.p's
How to rationalise compounds (4 points)
i) Change in electronegativity
ii) Pi-bonding
iii) Element size
iv) Vacant orbitals
Electronegative E - Is E-OH acidic or basic?
E-OH --> EO- + H+
Acidic
Electropositive E - Is E-OH acidic or basic?
E-OH --> E+ + OH-
Basic
VSEPR
Wade's Rules
1) Count all valence electrons
2) Divide by 2 to get no. of pairs
3) Subtract 1 pair for each exohedral B-H
4) Remaining pairs are PSEP's
5) N+1 = Closo
N+2 = Nido
N+3 = Arachno
(n = number of vertices)
Anomalies in periodicity
Usually reflect presence of d or f rows which have poor shielding
Borane reaction with base
[BnHn]2-
Boranes reaction with alkynes
Carboranes e.g. C2B10H12
Properties of silicones
Thermal oxidative stability
Flexible due to low energy bending of bonds
Hydrophobic
Me groups can be substituted
Formation of phosphazines
[NH4]Cl + PCl5 + heat
Bonding in phosphazines
Electrons donated from N lone pair to vacant sigma* orbital on P
Reaction of phosphazines with heat then nucleophile
Polymer with Cl groups substituted for Nu
Formation of S4N4 (and S8)
[NH4]Cl + S2Cl2 + heat
Reaction if S4N4 with heat and Ag
S2N2 and (S=N) polymer
Properties of (S=N) polymer
Metallic conductor
Low temperature superconductor
Formation of ammonia borane
MeNH2 + BH3
Effect if oxidation state on electronegativity
Higher oxidation state --> more electronegative
Heating ammonia borane
100C (-H2) - cyclic boron nitride
200C (-H2) - n methyl borazine (cf benzene)
Further heating - hexagonal boron nitride (cf graphite)
Very high temp and pressure - cubic boron nitride (cf diamond)
Formation of phosphazines
[NH4]Cl + PCl5 + heat
3 centre 2 electron bond
3 atoms share 2 electrons
E.g. B-H-B - one electron from each boron shared over the three atoms including H+
Why do 4p elements experience a greater effective nuclear charge?
Presence of 3d electrons - poor shielding. So electrons are held more tightly than would be expected.
Homonuclear bond energies
Weak between electronegative atoms due to lone pair repulsion. Decrease down a group as orbitals get bigger and overlap becomes poorer.
Heteronuclear bond energies
2A-B > A-A + B-B
Change in electronegativity strengthens the bond
Amphoterism
Can act as both acidic and basic
Structure of dihydrates
Larger atoms can support a larger CN and disfavour double bonds - so octahedral with (OH)6 is preferred.
Smaller atoms prefer a H bonded adduct with double bonds to oxygen.
Hydrolysis of xenon compounds
Leads to oxides, oxoanions and oxyfluorides
Affect of oxidation state on acidity
Higher oxidation state - more acidic
Oxidation of Xe2 to [Xe2]+
Makes it more stable as bond order increases from 0 to 0.5. Electrons removed from antibonding orbital.