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MA 105 Final EXAM Download answer at

http://www.supportonlineexam.com/product/ma-105-final-exam

About supportonlineexam ?

www.supportonlineexam.com

1)



2)




3)



4)



5)




Remaining roots are given by:



, therefore x=-1 is one of the roots, remaining roots are given by:



Remaining roots are given by:



So the roots are:



6)



Remaining roots are given by:



x=-1 is one of the roots because Q (-1) =0


By synthetic division:



Remaining roots are given by:



x=-3 is one of the roots, S (-3) =0


Remaining roots are given by:



Remaining roots are given by:



Hence the remaining roots are non-real.


Therefore real roots are:


x=1,-1,-3


7)



The function is not defined for x=-6 and x=5, so domain is:



Y-intercept is:


Plugging x=0:



X-intercept is:


Plugging y=0:



8)Circle with centre (-2,9) and radius 3 is:



9)



10)



Therefore conic section is Hyperbola.


11)



12)



13)



14)



15)



16)



Multiplying equation (2) by 9:



Adding these equations, we get:



Plugging y=-5 in equation (2)



17)


Let number of containers weighing 4 Kg =x


Let number of containers weighing 3 Kg =y


Therefore equations are:



Multiplying equation (1) by 4:



Subtracting equation (2) from equation (1):


y=20


Plugging y=20 in equation (1)



18)The solution set for system of inequalities is shown by green shaded region.

1)



2)




3)



4)



5)




Remaining roots are given by:



, therefore x=-1 is one of the roots, remaining roots are given by:



Remaining roots are given by:



So the roots are:



6)



Remaining roots are given by:



x=-1 is one of the roots because Q (-1) =0


By synthetic division:



Remaining roots are given by:



x=-3 is one of the roots, S (-3) =0


Remaining roots are given by:



Remaining roots are given by:



Hence the remaining roots are non-real.


Therefore real roots are:


x=1,-1,-3


7)



The function is not defined for x=-6 and x=5, so domain is:



Y-intercept is:


Plugging x=0:



X-intercept is:


Plugging y=0:



8)Circle with centre (-2,9) and radius 3 is:



9)



10)



Therefore conic section is Hyperbola.


11)



12)



13)



14)



15)



16)



Multiplying equation (2) by 9:



Adding these equations, we get:



Plugging y=-5 in equation (2)



17)


Let number of containers weighing 4 Kg =x


Let number of containers weighing 3 Kg =y


Therefore equations are:



Multiplying equation (1) by 4:



Subtracting equation (2) from equation (1):


y=20


Plugging y=20 in equation (1)



18)The solution set for system of inequalities is shown by green shaded region.