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33 Cards in this Set

  • Front
  • Back
row reduction allows us to :
1) Swap rows
2) Scale rows
3) Combine rows
Echelon form
1 pivot per row

Nothing to the left of a pivot in a row


Each pivot is further to the right than the pivot above

A pivot on the right most column means
There is no solution.
reduced echelon form
all pivots are '1'
only zeros in the same columns as pivots
trivial solution is
all zeros
homogeneous system is
set equal to zero
All homogeneous solutions have
-the origin as a solution
-can only have a non-trivial solution of you have a free variable
-the solution can be scaled and it is still a solution
-adding 2 solutions, also, yields a solution
the general solution =
homogenous solution + particular solution
# of free variables =
# of degrees of freedom & # of dimensions in answer
length
sqrt of all entries squared
dot product
the sum of all the products of corresponding vector entries
expeted value
probability vector (dot) outcome vector
v (dot) w , is also = to
[v][w]cos (theta)
v (dot) v =
[v]^2
perpendicular=
orthogonal= dot product is zero
a convex combination
xv+(1-x)w
the 3 properties of a sub set that are not necessarily inherited by a vector space:
1-includes the zero vector
2-closed under addition
3- closed under multiplication
if your matrix has free variables, then you set is linearly :
DEPENDENT
of your matrix does not have free variables, then your set is linearlly:
independent
when testing to see if a set or sub set is a vector space , be sure to test using -
scalar multiples of zero and negative 1
Span: ?
The set of all linear combinations of those vectors
when writing the span
include only the vectors of the free variables, surrounded by squiggle brackets
the only time when span is not infinite-
it is zero
linear independence:
a set of vectors is linearly independent if non of the vectors in the set is a linear combination of the other vectors. The opposite is linear DEPENDENCE.
can you make a linearly dependent set into an indep set by adding a vector?
NO
can you make a lin dep set into an indep set by subtracting a vector
YES
if S1 is a subset of s
1- if s1 is linearly indep so is the bigger set s
2- if the bigger set is linearly dep, then so is its small ser s1
can you add a vector to a lin indep set and make it dep?
YES

(so long as the vector you add in wasnt in the span of the origoinal vecotr)
Basis
A set of vectors that are:


1) Linearly independent


2) Span all of V

How to test for a basis?
1) pivots in all columns - (no free variables) = independent


2) pivots in all rows = spans whole set

** a little bonus to remember : given a vector space, there is exactly 1 way to express a vector (in the set of V) as a linear combination of the vectors from the basis.

angle between 2 vectors w and v:
cos(theta)= (w dot v)/ ([w][v])

What is a pivot element in the context of linear algebra?

The pivot element is an element on the left hand side of a matrix that you want elements above and below to be the value zero.

Are the vectors:




v1 = (2,2,0)


v2 = (1,-1,1)


v3 = (4,2,-2)




linearly independent?