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33 Cards in this Set
- Front
- Back
row reduction allows us to :
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1) Swap rows
2) Scale rows 3) Combine rows |
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Echelon form
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1 pivot per row
Nothing to the left of a pivot in a row Each pivot is further to the right than the pivot above |
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A pivot on the right most column means
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There is no solution.
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reduced echelon form
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all pivots are '1'
only zeros in the same columns as pivots |
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trivial solution is
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all zeros
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homogeneous system is
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set equal to zero
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All homogeneous solutions have
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-the origin as a solution
-can only have a non-trivial solution of you have a free variable -the solution can be scaled and it is still a solution -adding 2 solutions, also, yields a solution |
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the general solution =
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homogenous solution + particular solution
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# of free variables =
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# of degrees of freedom & # of dimensions in answer
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length
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sqrt of all entries squared
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dot product
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the sum of all the products of corresponding vector entries
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expeted value
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probability vector (dot) outcome vector
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v (dot) w , is also = to
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[v][w]cos (theta)
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v (dot) v =
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[v]^2
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perpendicular=
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orthogonal= dot product is zero
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a convex combination
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xv+(1-x)w
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the 3 properties of a sub set that are not necessarily inherited by a vector space:
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1-includes the zero vector
2-closed under addition 3- closed under multiplication |
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if your matrix has free variables, then you set is linearly :
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DEPENDENT
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of your matrix does not have free variables, then your set is linearlly:
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independent
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when testing to see if a set or sub set is a vector space , be sure to test using -
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scalar multiples of zero and negative 1
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Span: ?
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The set of all linear combinations of those vectors
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when writing the span
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include only the vectors of the free variables, surrounded by squiggle brackets
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the only time when span is not infinite-
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it is zero
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linear independence:
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a set of vectors is linearly independent if non of the vectors in the set is a linear combination of the other vectors. The opposite is linear DEPENDENCE.
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can you make a linearly dependent set into an indep set by adding a vector?
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NO
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can you make a lin dep set into an indep set by subtracting a vector
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YES
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if S1 is a subset of s
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1- if s1 is linearly indep so is the bigger set s
2- if the bigger set is linearly dep, then so is its small ser s1 |
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can you add a vector to a lin indep set and make it dep?
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YES
(so long as the vector you add in wasnt in the span of the origoinal vecotr) |
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Basis
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A set of vectors that are:
1) Linearly independent 2) Span all of V |
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How to test for a basis?
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1) pivots in all columns - (no free variables) = independent
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angle between 2 vectors w and v:
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cos(theta)= (w dot v)/ ([w][v])
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What is a pivot element in the context of linear algebra? |
The pivot element is an element on the left hand side of a matrix that you want elements above and below to be the value zero. |
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Are the vectors: v1 = (2,2,0) v2 = (1,-1,1) v3 = (4,2,-2) linearly independent? |
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