• Shuffle
    Toggle On
    Toggle Off
  • Alphabetize
    Toggle On
    Toggle Off
  • Front First
    Toggle On
    Toggle Off
  • Both Sides
    Toggle On
    Toggle Off
  • Read
    Toggle On
    Toggle Off
Reading...
Front

Card Range To Study

through

image

Play button

image

Play button

image

Progress

1/11

Click to flip

Use LEFT and RIGHT arrow keys to navigate between flashcards;

Use UP and DOWN arrow keys to flip the card;

H to show hint;

A reads text to speech;

11 Cards in this Set

  • Front
  • Back
In the negative feedback control of respiration, a high level of carbon dioxide in the blood will stimulate chemoreceptors. The chemoreceptors send information to the medulla in the brain stem. The medulla then stimulates an increase in respiratory rate.
1. The integrator in this system is:
A. The CO2
B. The chemoreceptors
C. The respiratory muscles
D. The medulla
E. None of the above
D. The medulla

rational: the medulla controls involuntary functions, such as breathing, heart rate, and blood pressure.
In the negative feedback control of respiration, a high level of carbon dioxide in the blood will stimulate chemoreceptors. The chemoreceptors send information to the medulla in the brain stem. The medulla then stimulates an increase in respiratory rate.


2. The effector in this system is:

A. The CO2
B. The chemoreceptors
C. The respiratory muscles
D. The medulla
E. None of the above
C. The respiratory muscles
3. Heavy exercise in a hot environment can create the following: low blood pressure → faster heart rate → decrease in heart pumping ability → lower blood pressure → even faster heart rate → further decrease in heart pumping ability … This cycle is:
A. Negative feedback
B. Positive feedback
C. Feed forward
D. A shift of a set point
E. Lack of an afferent pathway
B. Positive feedback
4. At the very beginning of exercise, our heart rate increases above the resting rate, in anticipation of the increased need during exercise. This is an example of:
A. A negative feedback mechanism
B. A positive feedback mechanism
C. A feed forward mechanism
D. Failure of the negative feedback control of heart rate
E. None of the above
C. A feed forward mechanism
5. Non polar molecules can easily enter the cell because:
A. They pass through water channels
B. The cell has many transporters for these molecules
C. They can pass through the lipid part of the cell membrane bilayer
D. They can pass through ion channels
E. None of the above
C. They can pass through the lipid part of the cell membrane bilayer
6. Smooth endoplasmic reticulum (ER) is important in the muscle cells because:
A. In stores and releases digestive enzymes
B. It stores, releases Ca++
C. It is involved in the synthesis of protein
D. It is the site for ATP production
E. Both B and C
B. It stores, releases Ca++
7. Which is NOT true about mitochondria
A. They have their own DNA
B. All catabolic (energy) pathways are located in the mitochondria
C. They are a membranous organelle
D. They are found in the cell
E. None of the above (all are true)
B. All catabolic (energy) pathways are located in the mitochondria
8. Concerning the following reaction: A+B→C+D, if C and D together have greater energy stored in the chemical bonds than A and B, which of the following is true?
A. This is an anabolic reaction
B. To occur, this reaction requires an addition of energy
C. Some energy is likely released as heat in this reaction
D. Both A and B
E. All of the above
E. All of the above
9. Which is true about enzymes
A. They speed up a reaction
B. They create new reactions
C. They tend to be used up quickly in the reaction
D. They prevent the release of heat during a reaction
E. All of the above
A. They speed up a reaction
10. If the reaction: A+B ↔ C+D is in equilibrium, and some of A and B are removed, you would predict:
A. The reaction will shift to the right, forming more C and D
B. The reaction will shift to the left, forming more A and B
C. The reaction rates will remain equal and opposite
B. The reaction will shift to the left, forming more A and B
11. During a sprint, the muscle cells of a sprinter primarily use anaerobic (no oxygen) glycolysis for energy. Preventing the conversion of pyruvate to lactate (lactic acid) would likely:
A. Stop the Krebs cycle from functioning
B. Slow oxidative phosphorylation
C. Slow glycolysis because NAD regeneration would depend on oxidative phosphorylation
D. Allow a sprinter to run much faster
E. Prevent all generation of ATP
C. Slow glycolysis because NAD regeneration would depend on oxidative phosphorylation