Gcse Algebra - Solving Linear Equations

Front 1

Solve: 7x + 5 = 54

Back 1

x = 7

Hint 1

If, when we add 5 to 7x we get 54. What must 7x have been before?

Front 2

Solve: 3x - 5 = 22

Back 2

x = 9

Hint 2

If, when we subtract 5 from 3x we get 22. What must 3x have been before?

Front 3

Solve: 5x - 6 = 14

Back 3

x = 4

Hint 3

If, when we subtract 6 from 5x we get 14. What must 5x have been before?

Front 4

Solve: 3x - 12 = 18

Back 4

x = 10

Hint 4

If, when we subtract 12 from 3x we get 18. What must 3x have been before?

Front 5

Solve: 5x - 13 = 22

Back 5

x = 7

Hint 5

If, when we subtract 13 from 5x we get 22. What must 5x have been before?

Front 6

Solve: 3x - 6 = -15

Back 6

x = -3

Hint 6

If, when we subtract 6 from 3x we get -15. What must 3x have been before?

Front 7

Solve: 6x - 11 = -23

Back 7

x = -2

Hint 7

If, when we subtract 11 from 6x we get -23. What must 6x have been before?

Front 8

Solve: 4x + 4 = 16

Back 8

x = 3

Hint 8

If, when we add 4 to 4x we get 16. What must 4x have been before?

Front 9

Solve: 9x + 14 = 23

Back 9

x = 1

Hint 9

If, when we add 14 to 9x we get 23. What must 9x have been before?

Front 10

Solve: 4x + 12 = 32

Back 10

x = 5

Hint 10

If, when we add 12 to 4x we get 32. What must 4x have been before?

Front 11

Solve: 5(4x + 14) = 30

Back 11

x = -2

Hint 11

When we multiply (4x + 14) by 5 we get 30. What must (4x + 14) have been before?

Front 12

Solve: 3(5x + 7) = 6

Back 12

x = -1

Hint 12

When we multiply (5x + 7) by 3 we get 6. What must (5x + 7) have been before?

Front 13

Solve: 2(3x - 13) = -20

Back 13

x = 1

Hint 13

When we multiply (3x - 13) by 2 we get -20. What must (3x - 13) have been before?

Front 14

Solve: 3(3x - 5) = 48

Back 14

x = 7

Hint 14

When we multiply (3x - 5) by 3 we get 48. What must (3x - 5) have been before?

Front 15

Solve: 5(2x + 7) = 75

Back 15

x = 4

Hint 15

When we multiply (2x + 7) by 5 we get 75. What must (2x + 7) have been before?

Front 16

Solve: 5(4x + 4) = 0

Back 16

x = -1

Hint 16

When we multiply (4x + 4) by 5 we get 0. What must (4x + 4) have been before?

Front 17

Solve: 5(2x - 10) = -10

Back 17

x = 4

Hint 17

When we multiply (2x - 10) by 5 we get -10. What must (2x - 10) have been before?

Front 18

Solve: 2(2x + 4) = 20

Back 18

x = 3

Hint 18

When we multiply (2x + 4) by 2 we get 20. What must (2x + 4) have been before?

Front 19

Solve: 3(5x - 12) = 69

Back 19

x = 7

Hint 19

When we multiply (5x - 12) by 3 we get 69. What must (5x - 12) have been before?

Front 20

Solve: 2(3x + 12) = 42

Back 20

x = 3

Hint 20

When we multiply (3x + 12) by 2 we get 42. What must (3x + 12) have been before?

Front 21

Solve: 4x + 6 = 2x + 22

Back 21

x = 8

Hint 21

Start by subtracting 2x from both sides...

Front 22

Solve: 5x + 13 = 3x + 7

Back 22

x = -3

Hint 22

Start by subtracting 3x from both sides...

Front 23

Solve: 12x + 9 = 9x + 15

Back 23

x = 2

Hint 23

Start by subtracting 9x from both sides...

Front 24

Solve: 4x + 9 = 3x + 10

Back 24

x = 1

Hint 24

Start by subtracting 3x from both sides...

Front 25

Solve: 9x + 12 = 2x + 61

Back 25

x = 7

Hint 25

Start by subtracting 2x from both sides...

Front 26

Solve: 5x + 5 = 2x + 2

Back 26

x = -1

Hint 26

Start by subtracting 2x from both sides...

Front 27

Solve: 7x + 6 = 4x + 21

Back 27

x = 5

Hint 27

Start by subtracting 4x from both sides...

Front 28

Solve: 8x + 10 = 4x + 6

Back 28

x = -1

Hint 28

Start by subtracting 4x from both sides...

Front 29

Solve: 5x + 13 = 3x + 27

Back 29

x = 7

Hint 29

Start by subtracting 3x from both sides...

Front 30

Solve: 5x + 6 = 4x + 14

Back 30

x = 8

Hint 30

Start by subtracting 4x from both sides...