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19 Cards in this Set
- Front
- Back
Transition vs intermediate
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Transition can not be detected intermediate can be detected and sometimes isolated |
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How is rate characterised?
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Rate = -d[reactant]/dt =d[product]/dt
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Rate for a general case with stoichiometry?
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aA + bB -> cC + dD Rate = -(1/a)d[A]/dt = -(1/b)d[B]/dt = (1/c)d[C]/dt = (1/d)d[D]/dt |
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Differential rate expression?
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Rate = -d[A]/dt = d[P]/dt = k([A]^m)([B]^n) |
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How is rate law determined?
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experimentally only (it cannot be deduced from the stoichimetry of the reaction) |
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First order reaction? units
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units of k = s⁻¹ |
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Second order reaction? units
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Rate = k[A]² or k[A][B] units of k = dm³ mol⁻¹ s⁻¹ |
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nth order rate constant units?
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1/conc^(n-1) x 1/time |
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isolation method?
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for large [B] ≈ constant ∴k` = k[B]^n Rate = k`[A]^m |
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Initial rate method?
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r₀ = k`[A]₀^m plotting logr₀ vs log[A]₀ gives a straight line with slope = m (order can be zero) |
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problem with initial rates?
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can be very inaccurate and is wasteful in reactants as you need multiple runs |
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Integrated rate law: zeroth order?
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-d[A]/dt = k => d[A] = -kdt =>∫d[A] = - k∫dt (between [A]₀/[A] and 0/t =>[A] - [A]₀ = -kt =>[A] = [A]₀ - kt |
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Integrated rate law: first-order?
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=>d[A]/[A] = -k dt =>∫1/[A] d[A] = -k∫dt =ln[A]₀/[A] = kt |
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Integrated rate law: secound order?
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=> ∫1/[A]² d[A] = kt => 1/[A] - 1/[A]₀ = kt |
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Half life for first and second order?
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constant for 1st order, increases as reaction proceeds for second order |
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Arrhenius equation?
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where A(pre-exponential factor) = the probabilitiy molecules meet in the correct orientation to react e^(-Ea/RT) = probabiliy molecules have enough energy to react |
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How does a catalyst work?
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gives an alternative reaction pathway with a lower activation energy
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Define molecularity, bimolecular, unimolecular and termolecular?
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-bimolecular reaction is one where two reactant molecules come together -unimolecular reaction is one where one molecule decomposes e.g. an intermediate -termolecular reaction is one where three reactant molecules come together |
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Steady state approximation?
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assume that one intermediate in the reaction mechanism is consumed as quickly as it is generated. (its concentration is constant) |