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34 Cards in this Set
- Front
- Back
- 3rd side (hint)
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WHAT ARRE THE 4 KEY WORDS TO REMEMBER OF APPLICAIONS OF NUMBER THEORY
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MENTAL MATH TECHNIQUES
PERMUTATIONS COMBINATIONS PROPRTIES OF REAL NUMBERS |
MENTAL MATH TECHNIQUES
PERMUTATIONS COMBINATIONS PROPERIES OF REAL NUMBERS |
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THE FIRST OF THE TWOD DISCRIPTORS OF APPS OF NUMBER THEORY-DISCRIPTOR 1
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USE PRINCIPLES OF NUMBER THEORY AND PROPERTIES OF OR DECIMAL BASED SYSTEM TO PERFORM ARITHEMTIC OPERATIONS MENTALLY OR QUICKLY
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THE FIRST OF THE TWOD DISCRIPTORS OF APPS OF NUMBER THEORY-DISCRIPTOR 2
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USE PERMUTATIONS AND COMBINATIONS TO SOLVE PROBLEMS
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THE FIRST OF THE TWOD DISCRIPTORS OF APPS OF NUMBER THEORY-DISCRIPTOR 3
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APPS PROBLEMS REQUIRING THE USE OF NUMBERS TO QUANTIFY MEASURES
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PRIME NUMBERS
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TWO FACTORS 1 AND ITSELF
THE PRIME NUMBERS BEGIN WITH 2 ZERO AND ONE ARE NOT PRIME NUMBERS |
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EXAMPLE OF A PRIME NUMBER
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11 IS PRIME: HAS EXACTLY TOW FACTORS 1 AND 11
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11 AND ?
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COMPOSITE NUMBER:
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MORE THAN TWO FACTORS
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EXAMPLE OF A COMPOSITE NUMBER
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24 IS A COMPOSITE HAS MOULTIPLE FACTORS- (1,2,3,4,5,6,7,8,12,24)
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COMPOSITE OF WHAT NUMBER?
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EVEN NUMBERS
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INTERGERS DIVISABLE BY 2
IF N=ANY INTERGER, THEN 2N+1 IS AN ODD NUMBER |
EN
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ODD NUMBERS OR INTERGERS
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INTEGERS DIVISABLE BY 2
IF N=ANY INTERGER, THEN 2N+1 IS AN ODD NUMBER |
ON
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PRIME FACTORIZATION, GCF
FACTORZATION OR FACTORING |
PROCESS USED TO REWRITE A COMPOSTIE NUMBER AS THE PRODUCT OF TWO OR MORE FACTORS
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PRIME FACTORIZATION, GCF
FACTORZATION OR FACTORING EXAMPLES |
ALL OF THESE ARE WAYS THE NUMBER 24 CAN BE FACTORED 24=1(24) OR 2(12) OR 3(8) PR 4(6)_-
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PRIME FACTORING
FACTORZATION OR FACTORING EXAMPLES-EXAMPLES |
24=(2)(2)(2)(2)
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GCF DEFINE
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LARGEST FACTOR BY WHICH TWO DIFFRIENT NUMBERS ARE DIVISIBLE
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GCF EXAMPLES-WHAT IS THE GCF OF 24 AND 32?
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MAKE A NUMBER TREE
24-BRANCH 1 (1,24) 24-BRANCH 2 (3,12) 24-BRANCH 3 (3,8) 24 BRANCH 4 (4.6) BANCH 2 BRANCH 1 (1<32) BRANCH 2 (2,16) BRANCH 3 (4,16) |
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MENTAL ARITHMATIC
DIVISIBILTY RULES |
DIVISIBLE BY 2: NUMBER IS EVEN
DIVISIBLE BY 3: SUM OF DIGITS DIVISIBLE BY 3 DIVISIBLE BY 5: NUMBER ENDS IN 0 OR 5 DIVISIBLE BY 6: EVEN NUMBER DIVSIBLE BY 3 DIVIISBLE BY 9: SUM OF DIGITS DIVISIBLE BY 9 DIVISIBLE BY 10: NUMBER ENDS IN 0 |
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QUICK ARITHIMATIC: N20 ARROW X2,X10
0n*25 |
100/4*100
17*25=/4, X100 Nx50=>/2, *100 |
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QUICK ARITHIMATIC:DIVISION
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N/20=> X2, X10
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PERCENTS AND FRACTIONS
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LEARN THE UNIT PERCENTS AND THEIR FRACTIONAL EQUIVALENTS AND THEN JUST USE MULTUIPLES
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unit prcent
unit fraction unit percent unit fraction |
1%
1/100 100% 1 |
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unit prcent
unit fraction unit percent unit fraction |
2%
1/50 50% 1/2 |
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unit prcent
unit fraction unit percent unit fraction |
4%
1/25 25% 1/4 |
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unit prcent
unit fraction unit percent unit fraction |
5%
1/20 20% 1/5 |
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unit prcent
unit fraction unit percent unit fraction |
33 1/3%
1/3 10% 1/10 |
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Lenth, area, Volume, capacity, density-LENTH
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MEASURS OF 1 DIEMENSION SUCH AS FET, INCHES, METERS, KILOMETERS, MILES
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Lenth, area, Volume, capacity, density-AREA
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MEASURE OF TWO DIMENSIONS OR PART OF SURFACE, SUCH AS FT^2, M^2, IN^3, CM^3
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Lenth, area, Volume, capacity, density-VOLUME
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MEASURE OF 3 DIMIENSIONS OR OCCUPIED BY SPACE, SUCH AS FT^3, m^3, CM^3
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Lenth, area, Volume, capacity, density-CAPACITY
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A MEASURE BASED ON THREE DIMENESIONS OR HOW MUCH SOMETHING WILL GOLD SUCH AS GALLONS, LITERS, PINTS, QUARTS, OUNCES
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Lenth, area, Volume, capacity, density-DENSITY
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DESITY IS PHYSICAL PROPERTY OF MATTER RELATED TO MASS AND VOLUME-DENSITY=MAS/VOL
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DURING TESTING YOU ARE PROVIDED WITH A CHART THAT HAS THE FOLLOWING FORMULAS
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CIRCUM CIRCLE
AREA: CIRCLE TRAINGLE, RHOMBUS, TRAPZOID, SURFACE AREA:SPHERE LATERAL AREA: CYLINDER vOLUME CLYINDER, CONE, SPHRE PRISM |
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WHICH OF THE 3 SHAPES ARE U UNSURE OF?
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RHOMBUS
TRAPEZOID SO STUDY AND UNDERSTAND THEM! |
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COUNTING TECHNIQUES:PERMUTATIONS
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AN ARRANGEMENT FO THE ELEMENTS FORM A GIVEN SENT IN A DEFINATE ORDER-GIVE {A, B. c} THERE ARE 6 DIFFIENT ARRANGEMENTS ABC, ACB, BAC, BCA, CZB, CBA-DO EXAMPLB PROMBEM ON PAGE 52
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COMBINATIONS COUNTING TECHNIQUES
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COMBINATIONS ARE UNIQUE SUBSETS OF THE ELEMENTS SET, REGARDLESS HOW THEY ARE ARRANGED-GIVEN {A,b,c} THERE IS 1 UNIQUE ARRANGEMENT BECAUSE EACH ARRANGEMENT HAS THE SAME LETTERS**DO THE EXAMPLE ON THE BOTTEM OF PAGE 52*****AND TOP OF 53***
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A FOURTH GRADE TEACHER WANTED T BUILD A SANDBOX FOR HER ROOM THAT SHE COULD USE TO TEACH STUDENTS ABOUT ARTIFACTS. THE bOX WAS TO BE FILLED TO A DEPTH O F15 INCHES AND HAD DIMENSITONS OF 5 FT BY 4 FT BY 3 FT BY 2 FT. iF ABOUT 1/4 A CUBIC FOOT WEITHS 10 POUNDS, HOW MANY POUNDS OF SAND ARE NEED TO FILL THE SANDBOX?
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DRAW A SANDBOX 5 ON THE BOTTEM LENGTH, 4 ON THE BOTTEM SIDE LENGTH, AND 2 ON THEH HIGHT =A 1000PDS FIRST CONVERT THE 15 INCHES TO FEET, 15/12=5/4 FOOT, v=BH=5 (4) =25FT^2 VOLUME =B * h
1/4FT^3=10 POUNDS SO 1 FT=40 POUN-SO THE AMOUNT OF SAND NEED IS 25(40) OR 1000 POUNDS OF SAND |
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