Simple Lab Report

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The objective of this lab was to brominate a hydrocarbon by converting 2,3-dimethyl butane to 2,3-dibromo-2,3-dimethyl-butane through crystallization. In order to verify the purity and the identity of the product two tests were done, one was using melting point and the other was NMR. The melting point range found in this test was between 138°C-175°C, whereas the ideal melting point for the product was 168°C. Based off of the melting point range, it can be assumed that the product had formed entirely because the ideal range, 168°C, was between the ranges found. The NMR results show that the product had formed, the ideal NMR shown on D2L show that a singlet peak should has formed at 2.0 (ppm). However, the results of the NMR found in the test show a triplet peak at 2.0 (ppm). Although the ideal peak and example peak are not perfectly equivalent, it still shows that the NMR peak had some source of the product there could have just been an impurity left behind. …show more content…
NMR spectrum A is the product because there is a simple peak at 2.0 (ppm). There is an even splitting with no neighboring protons, so only one peak will be present because all of the CH3s are equivalent. NMR spectrum B is the starting material because there are different types of protons present; there is hydrogen and two CH3 groups on each side, it is still symmetrical. So there will be two different peaks that will be shown in the NMR spectrum, which is represented as a doublet. The test NMR spectrum shows the one peak at 2.0 (ppm), which represents the product because of the chemical shift. The only difference is the splitting; the test NMR has 3 due to an impurity left

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