Rounding And Truncation

Improved Essays
Rounding and Truncation The teacher would award Student 1 an A for the class for earning 299 points out of a possible 334 points. The teacher will divide the number of points earned, 299, by the total possible points, 334, with the answer of 0.895. The teacher then multiplied this answer by 100 creating the number 89.5. This number is able to be rounded to the nearest ten percent, 90%. The student achieved the qualification for a grade of A. The student would not be given the grade of A if the teacher truncates the whole number. Truncating the number to the nearest whole, would leave the student with an 89%, thus keeping the student just under the requirement for an A. A taxpayer with an income tax rate of 27.8% would want to truncate …show more content…
When determining the safest baggage weight for an airplane, truncation would be best. The FAA (Federal Aviation Authority) works with airline manufacturers to determine the maximum allowable baggage weight for a plane so as not to be deemed too heavy to fly. If the average baggage weight of 56.8394951 pounds is found to be the tipping point, then truncating the weight to 56 pounds, or even 50 pounds will keep the average baggage weight well within safety parameters.
Truncation Example 2: In a classroom candy can be a great motivator. However, to be fair, and avoid conflicts the teacher needs to determine how much candy he or she can give each student. If the teacher has fourteen candies to give to three students each student should receive 4.66 pieces. Unfortunately it is not feasible to try to cut one candy into partial pieces. If the amount were rounded, to five pieces, someone would be disappointed, so truncating the amount to four pieces will give each child a fair
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The teacher will effectively create eleven total groups for this class since there are six groups of girls and five groups of boys. By adding the total number of groups for each gender, the sum is eleven. Also, the sum of all students is forty-four, and 44÷11=4, thus four students per group. The famous mathematician, Euclid, created a way to prove there are an infinite number of primes (numbers whose only factors are itself and one). Euclid’s theorem states, “Suppose that p1=2 < p2 = 3 < ... < pr are all of the primes. Let P = p1p2...pr+1 and let p be a prime dividing P; then p can not be any of p1, p2, ..., pr, otherwise p would divide the difference P-p1p2...pr=1, which is impossible. So this prime p is still another prime, and p1, p2, ..., pr would not be all of the primes.”(Ribenboim95, p.3) What Euclid meant was that you could choose a set of prime numbers (not necessarily consecutive) and multiply them together then add one. After performing the procedure, the sum cannot be divided by any of the primes in the original set, thus creating a new prime

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