Analysis Questions:
1. The primary reaction catalyzed by catalase is the decomposition of hydrogen peroxide to form water and oxygen, which occurs spontaneously, but not at a very rapid rate. Write a balanced equation for this reaction. Label the reactant and the product. (Remember that catalase is not a reactant or a product and can be written over the arrow separating the reactant from the products.) I will help you with the equation.
Catalase
2H2O2 ------------------------> 2H2O + O2 (g)
(Hydrogen peroxide) (Water) (Oxygen)
2. Explain why, in your first trial (Table 1), you used two test tubes, one with hydrogen peroxide and one with water.
The 1 test tube has liver and water this acts as a negative control indicating no reaction. …show more content…
Explain the results you obtained using a piece of muscle and a piece of potato?.
Both the test tubes will show decomposition of hydrogen peroxide because both potato and uncooked ham have catalase enzymes.
5. What effect did acetic acid (vinegar) have on the reaction? Why?
The catalase enzyme works best at pH 7 but it can perform well between 6.8 to 7.5. A 0.1 M Vinegar has a pH approximately 3. 2cm of them should have reduced the pH from 7 interfering with the breakdown of hydrogen peroxide. No reaction obtained.
6. What effect did ammonium hydroxide have on the reaction? Why? 0.1M of ammonium hydroxide has a pH approximately 11, which again inhibits the enzyme activity.
7. If an enzyme is boiled, what happens to the enzyme?
The enzyme loses its secondary and tertiary structure. Altering the structures will stop its enzymatic activity.
8. If the enzyme is frozen what happens enzyme activity? Why? The frozen enzymes have their active site frozen so the enzymatic activity comes to nil. But it resumes back when the temperature is optimum.
The frozen enzymes have their active site frozen so the enzymatic activity comes to nil. But it resumes back when the temperature is
1. The primary reaction catalyzed by catalase is the decomposition of hydrogen peroxide to form water and oxygen, which occurs spontaneously, but not at a very rapid rate. Write a balanced equation for this reaction. Label the reactant and the product. (Remember that catalase is not a reactant or a product and can be written over the arrow separating the reactant from the products.) I will help you with the equation.
Catalase
2H2O2 ------------------------> 2H2O + O2 (g)
(Hydrogen peroxide) (Water) (Oxygen)
2. Explain why, in your first trial (Table 1), you used two test tubes, one with hydrogen peroxide and one with water.
The 1 test tube has liver and water this acts as a negative control indicating no reaction. …show more content…
Explain the results you obtained using a piece of muscle and a piece of potato?.
Both the test tubes will show decomposition of hydrogen peroxide because both potato and uncooked ham have catalase enzymes.
5. What effect did acetic acid (vinegar) have on the reaction? Why?
The catalase enzyme works best at pH 7 but it can perform well between 6.8 to 7.5. A 0.1 M Vinegar has a pH approximately 3. 2cm of them should have reduced the pH from 7 interfering with the breakdown of hydrogen peroxide. No reaction obtained.
6. What effect did ammonium hydroxide have on the reaction? Why? 0.1M of ammonium hydroxide has a pH approximately 11, which again inhibits the enzyme activity.
7. If an enzyme is boiled, what happens to the enzyme?
The enzyme loses its secondary and tertiary structure. Altering the structures will stop its enzymatic activity.
8. If the enzyme is frozen what happens enzyme activity? Why? The frozen enzymes have their active site frozen so the enzymatic activity comes to nil. But it resumes back when the temperature is optimum.
The frozen enzymes have their active site frozen so the enzymatic activity comes to nil. But it resumes back when the temperature is