9, 11, 6, 10, 7, 4, 0, 7, 8, 6, 8, 2, 18
The sample average is 7.38. Is that close enough to 7 so that we should accept the hypothesis? Or is it too far away? We know that if the hypothesis is true, then will have a normal distribution with mean μ = 7 and variance 16.16/n. So, there …show more content…
So, t will be our test statistic. In our case, the computed value of t is .341, which is well within the zone of acceptance. So we can accept the hypothesis that μ = 7.
The Independent Samples t-Test can only associate the means for two (and only two) groups. It cannot make comparisons among more than two groups. If you wish to compare the means across more than two groups, you will likely want to run an ANOVA.
The Dependent Samples t-test (also called the paired t-test or paired-samples t-test) compares the means of two related groups to detect whether there are any statistically significant differences between these