Glycolysis Lab Report

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1. Glycolysis

a. Indicate at what stage the compound is officially no longer a sugar, and why?

The compound is no longer a sugar is at stage five. This is because the fructose 1,6 bisphosphate in stage four, breaks down from a six carbon sugar to two, three carbon molecules. The first one being dihydroxyacetone phosphate (DHAP) and the other being glyceraldehyde 3-phosphate (G3P).

b. Indicate how the glucose enters the cell

The glucose enters the cell through facilitated diffusion because it’s a large molecule and only small, and non-polar molecules can pass through the membrane via simple diffusion. Facilitated diffusion occurs with the help of carrier proteins, which shuttles the molecules across the cell’s membrane without using
…show more content…
2. Energy Yield of tetracosanoic (lignoceric) acid

Molecular Formula: C24H48O2
• This will produce 12 acetyl groups and 11 rounds of beta oxidation

• 11 rounds of beta oxidation will produce
- 11 FADH2, which will produce 22 ATP (11 * 2)
- 11 NADH, which will produce 33 ATP (11 * 3)

• 12 acetyl groups will go through the citric acid cycle and produce
- 12 FADH2, which will produce 24 ATP (12 * 2)
- 36 NADH, which will produce 108 ATP (36 * 3)
- 12 ATP

Total ATP produced is:
= 22 + 33 + 24 + 108 + 12
= 199 – 2 (2 ATPS were invested)
= 197

Therefore, the total number of ATP produced from one molecule of tetracosanoic (lignoceric) acid is 197.

3. Comparing Energy Yields

• Stachyose

= 144 ATP 24 C
= 6

• Tetracosanoic (lignoceric) acid

= 197 ATP 24 C
=

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