The appropriate units for the constant is kPa/K as the pressure is measured in kPa and the temperature is measured in Kelvin and Pressure was divided by Temperature. The expected pressure of the gaseous sample at a temperature of -50 degree Celsius or 223 Kelvin is calculated to be 72.525kPa and the pressure at a temperature of 200 degree Celsius or 473 Kelvin is calculated to be 153.83kPa using the constant .3252225kPa/K and the equation P=TK according to Gay-Lussac 's Law. The expected pressures of the gaseous sample at temperatures of 223Kelvin and 473Kelvin, using the equation for the trendline in the Part B graph y=0.2643x+19.98, is calculated to be 78.9189kPa and 144.9939kPa respectively. The results are similar but not quite exact compared to the calculated pressures from question 7. A source of error within the experiment that could account for this discrepancy could be the fact that the constant is made up of only the averages of four values compared to the numerous data pairs that the graph uses. A difference in constant may cause differences in the calculated
The appropriate units for the constant is kPa/K as the pressure is measured in kPa and the temperature is measured in Kelvin and Pressure was divided by Temperature. The expected pressure of the gaseous sample at a temperature of -50 degree Celsius or 223 Kelvin is calculated to be 72.525kPa and the pressure at a temperature of 200 degree Celsius or 473 Kelvin is calculated to be 153.83kPa using the constant .3252225kPa/K and the equation P=TK according to Gay-Lussac 's Law. The expected pressures of the gaseous sample at temperatures of 223Kelvin and 473Kelvin, using the equation for the trendline in the Part B graph y=0.2643x+19.98, is calculated to be 78.9189kPa and 144.9939kPa respectively. The results are similar but not quite exact compared to the calculated pressures from question 7. A source of error within the experiment that could account for this discrepancy could be the fact that the constant is made up of only the averages of four values compared to the numerous data pairs that the graph uses. A difference in constant may cause differences in the calculated