F= Frictional force between tyres and road
F=ma^c
F=(mv^2)/r
It is true that for any given set of tyres and road conditions, there is a limit to the maximum frictional force that can be provided by the tyres. To bend at high …show more content…
The same concept applies of railroads, where inclination is used to avoid wear and tear. Since the mass of a train is great, the centripetal force exerted by a non-inclined rail onto the train makes one side of the rail wear off much more quickly than the other side. Inclination of rail tracks will balance the wear on both sides, increasing the time between replacements of the rail and reducing the risk of failure to corner at a bend.
Mechanism: Application of Uniform Circular Motion: Tilting In Train
High competition from other means of transportation have driven railway companies for increased performance, which means shorter time for travelling and improving the ride comfort. Railways for high speed trains are railways for trains that operate 200km/h to 300km/h, according to council of European Union. Travelling at high speed on flat tracks will affect passenger comfort severely as the centripetal force during cornering increases.
F=(mv^2)/r
F∝v^2
Therefore at higher speed, centripetal force increases.