CONCLUSION
An experiment was run to determine how a cell’s surface area to volume ratio affects its rate of diffusion. The proposed hypothesis was if a big surface area to volume ratio is something very desired by cells that need efficient and fast diffusion for their functioning (Oxygen, water, and waste), then the cube with the largest Surface area will have the most molecules diffused into the agar cube because the more surface area a cube have, the more molecules the agar cube is getting per minute and thus the rate of diffusion will be faster. The experimental data show that the bigger is the surface area to volume ratio, the bigger is the percentage volume of diffusion, so the rate of diffusion of pigment from the agar cube. The result of this lab was that the block with the highest class average …show more content…
The second highest diffusion class average rate was with the block with the second highest surface area to volume ratio (3:1). That rate was 72.4%. The lowest class average diffusion rate was the block with the smallest surface area to volume ratio (2:1). That block only had a diffusion rate of 49.3%. It can be concluded then that the higher the surface area to volume ratios, the higher the diffusion rates. Therefore the lower the surface area to volume ratios, the lower the diffusion rates.
The regard to the precision of the data three trials was run to reinforce consistency using three different sized cubes, each one representing a process of diffusion occurring in different sized cells. To find out the amount of molecule that diffused into the cube is to subtract the surface area and volume of the cubes after diffusion from the original surface area and volume of the cube before diffusion ( original SA/V-SA/V after diffusion= volume diffused into the cube). The amount it diffused in small size was 1cm, in
An experiment was run to determine how a cell’s surface area to volume ratio affects its rate of diffusion. The proposed hypothesis was if a big surface area to volume ratio is something very desired by cells that need efficient and fast diffusion for their functioning (Oxygen, water, and waste), then the cube with the largest Surface area will have the most molecules diffused into the agar cube because the more surface area a cube have, the more molecules the agar cube is getting per minute and thus the rate of diffusion will be faster. The experimental data show that the bigger is the surface area to volume ratio, the bigger is the percentage volume of diffusion, so the rate of diffusion of pigment from the agar cube. The result of this lab was that the block with the highest class average …show more content…
The second highest diffusion class average rate was with the block with the second highest surface area to volume ratio (3:1). That rate was 72.4%. The lowest class average diffusion rate was the block with the smallest surface area to volume ratio (2:1). That block only had a diffusion rate of 49.3%. It can be concluded then that the higher the surface area to volume ratios, the higher the diffusion rates. Therefore the lower the surface area to volume ratios, the lower the diffusion rates.
The regard to the precision of the data three trials was run to reinforce consistency using three different sized cubes, each one representing a process of diffusion occurring in different sized cells. To find out the amount of molecule that diffused into the cube is to subtract the surface area and volume of the cubes after diffusion from the original surface area and volume of the cube before diffusion ( original SA/V-SA/V after diffusion= volume diffused into the cube). The amount it diffused in small size was 1cm, in