Eukaryotic cells are known for its organelles variety. Each organelle has its function so consequently each organelle differentiates from one another by its content. In this lab, the cells from a cauliflower were studied with the purpose to separate nuclei and mitochondria content from a solution. To achieve the results, the cauliflower solution had to go through differential centrifugation, microscopy, and succinate dehydrogenase assay.
For the fist part of the lab density played a key role in the separation of the cells content because mitochondria and nuclei are very different in size, mitochondria is approximately ten times smaller than nuclei. So it was hypothesized that nuclei would be present in pallet 1, and mitochondrial would be the content for pallet two because the density difference between the two organelles. During the microscopy, the solutions were analyzed, and clear show that P1 content was full of nuclei material (Figure 1). The other samples, S1, S2, and P2, shows a minimum amount of nuclei indicating the possibility of nuclei material. In figure 1 all the examples show that the nuclei had busted so that could have lead to nuclei “contamination” in S1, S2, and P2.
Even though the microscopy shows good results, it was necessary to proceed with succinate dehydrogenase assay procedure. In …show more content…
The results would show what was the relating on the activity of SDH with the concentration of the P2 solution. It was possible to see that the amount of activity was related to the quantity of mitochondria present in the sample. According to figure 3, P2B show saturation in the sample that lead to high activity (0.004mol/min). After achieving a “saturation”, the activity starts to decrease again, P2C 0.001mol/min. Figure 3 is an example of action potential where activity will be significant increase in certain quantity however it will start to decrease when it achieve a particular Plato (Chen,
For the fist part of the lab density played a key role in the separation of the cells content because mitochondria and nuclei are very different in size, mitochondria is approximately ten times smaller than nuclei. So it was hypothesized that nuclei would be present in pallet 1, and mitochondrial would be the content for pallet two because the density difference between the two organelles. During the microscopy, the solutions were analyzed, and clear show that P1 content was full of nuclei material (Figure 1). The other samples, S1, S2, and P2, shows a minimum amount of nuclei indicating the possibility of nuclei material. In figure 1 all the examples show that the nuclei had busted so that could have lead to nuclei “contamination” in S1, S2, and P2.
Even though the microscopy shows good results, it was necessary to proceed with succinate dehydrogenase assay procedure. In …show more content…
The results would show what was the relating on the activity of SDH with the concentration of the P2 solution. It was possible to see that the amount of activity was related to the quantity of mitochondria present in the sample. According to figure 3, P2B show saturation in the sample that lead to high activity (0.004mol/min). After achieving a “saturation”, the activity starts to decrease again, P2C 0.001mol/min. Figure 3 is an example of action potential where activity will be significant increase in certain quantity however it will start to decrease when it achieve a particular Plato (Chen,