The purpose of this experiment was to ascertain an unidentified substance. The substance in question was a colorless liquid with an odor resembling acetone. To start with the Tollens’ test was conducted on the unidentified substance to differentiate between an aldehyde and a ketone. The results of the test were negative. This indicated that the substance under consideration was a ketone
The next step consisted of determining the melting point of the substance, which was in the range 99°C-102°C, which was very close to the literature value of102°C. The melting point of its derivative was 118°C-128°C, which was lower than the literature value of 144°C, indicating that there were some impurities in the substance. A possible reason for the lower melting point of the derivative could be the presence of moisture.
This was followed by the NMR analysis and IR spectroscopy. Based on the NMR analysis, it was concluded that the compound was 2-pentanone. There was a confirmation of 4 distinct peaks, reflecting the 4 distinct types of hydrogen. The area represented by the 4 peaks was 10, which …show more content…
There was a confirmation of 4 distinct peaks, reflecting the 4 distinct types of hydrogen. The area represented by the 4 peaks was 10, which confirmed the empirical formula of C5H10O. The figure shows the areas at the top of each peak and this reflects the total hydrogen atoms that are responsible for producing the signal. The 2 peaks shown at d 2.4 and d 2.1 relate to the hydrogens on the carbon adjacent to the carbonyl with absorption in the range d 2 and d 3. The other 2 signals at d 0.9 and d 1.61 relate to hydrogen as opposed to carbon primary and secondary respectively. Peak number 1 at d 2.4 has a multiplicity of 3, peak number 3 at d 1.61 has a multiplicity of 6, and peak number 4 at d 0.9 has a multiplicity of 3. The deductions made, confirmed the choice of
The next step consisted of determining the melting point of the substance, which was in the range 99°C-102°C, which was very close to the literature value of102°C. The melting point of its derivative was 118°C-128°C, which was lower than the literature value of 144°C, indicating that there were some impurities in the substance. A possible reason for the lower melting point of the derivative could be the presence of moisture.
This was followed by the NMR analysis and IR spectroscopy. Based on the NMR analysis, it was concluded that the compound was 2-pentanone. There was a confirmation of 4 distinct peaks, reflecting the 4 distinct types of hydrogen. The area represented by the 4 peaks was 10, which …show more content…
There was a confirmation of 4 distinct peaks, reflecting the 4 distinct types of hydrogen. The area represented by the 4 peaks was 10, which confirmed the empirical formula of C5H10O. The figure shows the areas at the top of each peak and this reflects the total hydrogen atoms that are responsible for producing the signal. The 2 peaks shown at d 2.4 and d 2.1 relate to the hydrogens on the carbon adjacent to the carbonyl with absorption in the range d 2 and d 3. The other 2 signals at d 0.9 and d 1.61 relate to hydrogen as opposed to carbon primary and secondary respectively. Peak number 1 at d 2.4 has a multiplicity of 3, peak number 3 at d 1.61 has a multiplicity of 6, and peak number 4 at d 0.9 has a multiplicity of 3. The deductions made, confirmed the choice of